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trunc

eq1:(trunc(ln(5)))!;

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trunc

trunc(6521/1000);

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trunc

eq1:(trunc(5))!;

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trunc

trunc(6521/1000);

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trunc

16 * (trunc(255/ 16) ...

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trunc

eq1:(trunc(5))!;

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trunc

expr: 62 - (999999 * ...

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trunc

trunc(6521/1000);

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trunc

eq1:(trunc(ln(100000)...

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trunc

Run Example
(%i1)niceindices(powerseries(%e^x, x, 0));
                                   inf
                                   ====   i
                                   \     x
(%o1)                               >    --
                                   /     i!
                                   ====
                                   i = 0
(%i2) taylor(%e^x, x, 0, 6);
                            2    3    4    5     6
                           x    x    x    x     x
(%o2)/T/           1 + x + -- + -- + -- + --- + --- + . . .
                           2    6    24   120   720
(%i3) plot2d([trunc(taylor(%e^x, x, 0, 6)), %e^x], [x,-5,5]);
plotplot2d([trunc(taylor(%e^x, x, 0, 6)), %e^x], [x,-5,5]);
Run Example
? trunc;

 -- Function: trunc (<expr>)
     Annotates the internal representation of the general expression
     <expr> so that it is displayed as if its sums were truncated
     Taylor series.  <expr> is not otherwise modified.

     Example:

          (%i1) expr: x^2 + x + 1;
                                      2
          (%o1)                      x  + x + 1
          (%i2) trunc (expr);
                                          2
          (%o2)                  1 + x + x  + . . .
          (%i3) is (expr = trunc (expr));
          (%o3)                         true


  There are also some inexact matches for `trunc'.
  Try `?? trunc' to see them.

(%o1)                                true
(%i2) 
Run Example
taylor( %e^(cos(x)-1) ,x , 0, 2);
                                     2
                                    x
(%o1)/T/                        1 - -- + . . .
                                    2
(%i2) plot2d([trunc(%), %e^x], [x,-5,5]);
plotplot2d([trunc(%), %e^x], [x,-5,5]);

Related Help

Help for Trunc