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limsubst

Run Example
(%i1)limsubst:true;
(%o1)                                true
(%i2) 
Run Example
? limsubst;

 -- Option variable: limsubst
     default value: `false' - prevents `limit' from attempting
     substitutions on unknown forms.  This is to avoid bugs like `limit
     (f(n)/f(n+1), n, inf)' giving 1.  Setting `limsubst' to `true'
     will allow such substitutions.


(%o1)                                true
(%i2) 
Run Example
f:x*(1-x)^(n-1)/(1-(1-x)^n);
                                       n - 1
                                (1 - x)      x
(%o1)                           --------------
                                            n
                                 1 - (1 - x)
(%i2) limsubst:false;
(%o2)                                false
(%i3) limit(f,x,0,plus);
                                       1
(%o3)                                  -
                                       n
(%i4) 

Related Help

Help for Limsubst